## The Quadratic Formula

The quadratic formula can find the *x* – intercepts for any quadratic equation written in standard form. To use the formula you just identify the coefficients and plug their values into the equation, and then follow the order of operations.

In this section we show where the formula comes from and guide you through using it. A few pitfalls and misconceptions are covered, so be sure to read through the notes, taking notes of your own. Then, watch the video and try the practice problems.

As always, be patient with yourself. Learning new things requires that you work through confusion and often frustration to boot!

Let’s take the generic quadratic equation, in standard form, and use what we know about completing the square to solve for *x*.

We have solved any and all quadratic equations here. Instead of having to follow this process repeatedly, for specific quadratic equations, we can jump to the final result and just plug in values of *a*, *b* and *c*, to find the *x* – intercepts.

However, if the equation is factorable, one should use their factoring skills to find the intercepts. If the equation is written in vertex form, they should use inverse operations to solve for the *x* – intercepts. When those methods fail is when quadratic formula should be used.

Let’s see how the equation works for an equation that IS factorable. Then, we’ll see how it works out when the equation was NOT factorable.

Example 1: Use the Quadratic Formula to find the *x* – intercepts of the following.

Write the formula first. This will help you keep track of how to plug in the numbers correctly, and help you to memorize the formula. Even if the formula is provided in reference, you’ll be likely to mess up signs or the order of the letters if you aren’t familiar with it.

Now, identify *a*, *b* and *c*, from the equation or function provided.

*a* = 1, *b* = 6, *c* = 8

Plug in the values, be careful of the signs and to maintain the order of operations. Parenthesis can be particularly useful, especially with one of the values is negative.

Now, simplify the formula following the order of operations. Square *b*, and multiply – 4 with *a* and *c*. In the denominator multiply 2 and *a*. Take the negative of *b* for the numerator outside of the square root.

If possible, simplify the square root, then reduce, if possible.

Here we have two answers, – 6 + 2, divided by 2, and – 6 – 2, divided by 2.

So the *x* – intercepts are (-2, 0) and (-4, 0). However, this was factorable, which is WAY simpler.

*x*^{2} + 6*x* + 8 = 0

(*x* + 4)(*x* + 2) = 0

*x* = – 4 and *x* = – 2

So, unless you’re required to, or cannot factor, do not use the quadratic formula as you’ll be more likely to make mistakes, and it is far more time consuming.

Let’s see another example, this one from an equation that is not factorable.

Here we have *a* = 3, *b* = – 8, and *c* = – 4. Let’s plug those values into the equation.

To see if the square root of 112 can be simplified, divide it by 4, if possible. It turns out you can divide by 4, twice, or 16, 7 times.

To figure out the approximations, to make finding these numbers on number line (like the *x* – axis) easier, we just approximate the square root of 7, then perform the calculation.

**Number of Solutions**

You can determine if a quadratic equation will have no *x* – intercepts by performing the quadratic formula’s operations. If the square root’s radicand is negative, after being simplified, there are no *x* – intercepts. The same was true when solving using completing the square.

This is useful information because it can save a lot of time. If you look at the radicand of the formula and determine that it will be negative for a given equation, then you do not need to carry out the calculations completely. There will be no *x* – intercepts, which is all you’ll need to know, (at this level).

Let’s see specifically what it is we’re talking about here. The square root portion of the quadratic formula is as follows.

No matter what, the first term of the radicand, (*b*^{2}), will be positive because it is squared. If that value is smaller than 4 times *a* times *c*, then the radicand is negative, since the 4*ac* is being subtracted from *b*^{2}.

If *b*^{2} – 4*ac *= 0, then because the square root of zero is just zero, there will be only one *x* – intercept. So, if *b*^{2} = 4*ac*, there will be exactly one *x* – intercept.

If *b*^{2} is larger than 4*ac¸*then the radicand will be a positive number, which will have two square root values. In this case, there will be two *x* – intercepts.

The radicand of the quadratic formula is called the **discriminant , **which is used to determine the number of solutions to the quadratic equation. Here’s a quick reference for the discriminant.

Last Note:

It is typically the case that when dealing with the quadratic formula you will be using a calculator. Be sure to round correctly, but not until the very last step. Rounding too soon on a calculator will create compounding errors, making your final answer wrong. This happens because when you round an irrational number, like the square root of 13, you are creating an acceptable error. When you perform further calculation, like say multiplying that approximation by 2, you have doubled the size of that acceptable error. Sometimes that is enough to make the error in approximation too large to be acceptable.

Coming Soon